Windows Maven runas

Rather than passing user.home to the JVM as shown below, a better fix, which requires a registry change, can be found here.

I created a new Windows' account called tomcat and wanted to start my web application using Maven's maven-tomcat-plugin for debugging purposes . 

From my "normal" Windows' account, I started a new command prompt window for the:
tomcat user as follows:

C:\Users\wnpr>runas /user:tomcat cmd
Geben Sie das Kennwort für "tomcat" ein:
Es wird versucht, cmd als Benutzer "GFT6841\tomcat" zu starten...

C:\Users\wnpr>

In the newly opened window, I tried to clean the project using Maven.

>mvn clean
Could not create local repository at C:\Users\Administrator\.m2\repository -> [Help 1]

My first attempt to solve this issue was taken from stackoverflow and involved creating a .m2 folder in the tomcat user's home directory and to copying a settings.xml file into the folder and, in the settings.xml file, setting the "localRepository" XML element to point to the actual repository's location, which existed in my normal user's directory; namely: "C:\Users\wnpr\.m2\repository"; however, this still didn't help.  

Then I tried to hard code it in the MAVEN_HOME\bin\m2.conf file, see below, but this didn't change anything either.

set maven.home default ${user.home}/.m2

Next, I tried to pass it to Maven as a run time parameter
>mvn  clean -Duser.home=c:\Users\wnpr 

This helped for clean and compiling but not exactly for running the application.

:Error creating bean with name org.springframework.security.extensions.kerberos.SunJaasKerberosTicketValidator defined in class path resource [applicationContext-security.xml]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Cannot locate default realm

Which is a Kerberos error and not a tomcat one. For the solution see here.